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Periodic Functions

Lots of things repeat: the height of a seat on a Ferris wheel, the tides, the phases of the moon, your heartbeat. A function whose graph repeats in a regular pattern is periodic. Once you know one cycle, you can predict the function’s value at any time, past or future.

  • A periodic function repeats its values at regular intervals.
  • One complete repetition of the pattern is a cycle.
  • The period is the horizontal length of one cycle, often a time.
  • The axis of the curve is the horizontal line halfway between the maximum and minimum:
y=max+min2y = \frac{\text{max} + \text{min}}{2}
  • The amplitude is the vertical distance from the axis to a maximum (or minimum):
amplitude=max−min2\text{amplitude} = \frac{\text{max} - \text{min}}{2}

The amplitude is always positive.

Height of a Ferris wheel rider over 20 seconds. The graph repeats every 10 seconds, between a minimum of 2 m and a maximum of 22 m, around the axis h = 12 m. Amplitude 10 m. 5 10 15 4 8 12 16 20 24 axis: h = 12 period = 10 s amplitude = 10 m time (s) height (m)
A Ferris wheel rider’s height: period 1010 s, maximum 2222 m, minimum 22 m.

Because the pattern repeats, adding or subtracting a whole number of periods doesn’t change the value:

f(x+period)=f(x)f(x + \text{period}) = f(x)

To predict far into the future, subtract as many full periods as you can, then read the value from the first cycle.

Use the Ferris wheel graph above to find the period, maximum, minimum, axis, and amplitude.

Solution. The peaks are at 55 s and 1515 s, so the period is 15−5=1015 - 5 = 10 s.

The maximum height is 2222 m and the minimum is 22 m.

axis: h=22+22=12,amplitude=22−22=10\text{axis: } h = \frac{22 + 2}{2} = 12, \qquad \text{amplitude} = \frac{22 - 2}{2} = 10

The axis is h=12h = 12 m and the amplitude is 1010 m. (The wheel’s centre is 1212 m up, and its radius is 1010 m.)

The water depth at a dock is measured every 22 hours:

Time (h)00224466881010121214141616
Depth (m)2.02.03.253.255.755.757.07.05.755.753.253.252.02.03.253.255.755.75

Find the period, amplitude, and axis, and predict the depth at 3030 hours.

Solution. The depth is 2.02.0 m at 00 h and again at 1212 h, and the pattern repeats, so the period is 1212 h.

Maximum 7.07.0, minimum 2.02.0: amplitude =7.0−2.02=2.5= \tfrac{7.0 - 2.0}{2} = 2.5 m, axis =7.0+2.02=4.5= \tfrac{7.0 + 2.0}{2} = 4.5 m.

At 3030 h: subtract two periods, 30−24=630 - 24 = 6, so the depth is the same as at 66 h: 7.07.0 m.

Is each situation periodic?

(a) the height of the tip of a clock’s minute hand

(b) the height of a tree over many years

(c) the number of hours of daylight each day over several years

Solution.

(a) Periodic, with a period of 6060 minutes.

(b) Not periodic. A tree grows taller; it doesn’t repeat.

(c) Periodic, with a period of about 11 year (about 365365 days).

A periodic function ff has a period of 88, and f(3)=5f(3) = 5. Find f(19)f(19) and f(−5)f(-5).

Solution. 19=3+2(8)19 = 3 + 2(8), so f(19)=f(3)=5f(19) = f(3) = 5.

−5=3−8-5 = 3 - 8, so f(−5)=f(3)=5f(-5) = f(3) = 5.

Measuring the period from a peak to a trough. That’s only half a cycle. Measure from one peak to the next peak, or between any two matching points.

Forgetting to halve. The amplitude is half the distance from maximum to minimum, not the whole distance.

Taking the axis as 00. The axis is halfway between the maximum and minimum, which is often not the xx-axis.

Predicting with a partial period. When extrapolating, subtract whole periods only.

1. (Warm-up) A periodic function has a maximum of 1010 and a minimum of 44. Find its amplitude and the equation of its axis.

Solution

Amplitude =10−42=3= \tfrac{10 - 4}{2} = 3. Axis: y=10+42=7y = \tfrac{10 + 4}{2} = 7.

2. (Warm-up) A resting heart beats once every 0.80.8 seconds. What is the period of the heartbeat?

Solution

0.80.8 seconds.

3. (Warm-up) Which are periodic?

  • (a) the height of a swinging pendulum’s bob
  • (b) your height as you grow up
  • (c) the phases of the moon
Solution

(a) and (c) are periodic. (b) isn’t: you don’t shrink and grow again in a cycle.

4. (Core) A periodic function has period 66, and f(2)=−1f(2) = -1. Find f(14)f(14) and f(−4)f(-4).

Solution

14=2+2(6)14 = 2 + 2(6) and −4=2−6-4 = 2 - 6, so both equal f(2)=−1f(2) = -1.

5. (Core) A Ferris wheel has a diameter of 3030 m. Its lowest point is 22 m above the ground, and it makes one revolution every 4040 s. Find the maximum height, amplitude, axis, and period of a rider’s height.

Solution

Maximum =2+30=32= 2 + 30 = 32 m, minimum =2= 2 m.

Amplitude =32−22=15= \tfrac{32 - 2}{2} = 15 m (the radius). Axis: h=32+22=17h = \tfrac{32 + 2}{2} = 17 m (the height of the centre). Period: 4040 s.

6. (Core) Using the dock table in Example 2, predict the depth at 4040 hours.

Solution

40−3(12)=440 - 3(12) = 4, so the depth matches the 44-hour value: 5.755.75 m.

7. (Core) A periodic function has a maximum of 33 and an amplitude of 55. What is its minimum, and what is its axis?

Solution

The axis is 55 below the maximum: y=3−5=−2y = 3 - 5 = -2. The minimum is 55 below the axis: −2−5=−7-2 - 5 = -7.

8. (Challenge) A bike pedal is 1717 cm from the centre of the crank, and the centre is 3030 cm above the ground. The pedal makes one full turn every 0.750.75 s. Find the maximum and minimum heights of the pedal, the amplitude, the axis, and the period, and describe the graph of its height over 33 seconds.

Solution

Maximum =30+17=47= 30 + 17 = 47 cm, minimum =30−17=13= 30 - 17 = 13 cm. Amplitude 1717 cm, axis h=30h = 30 cm, period 0.750.75 s.

Over 33 seconds the graph completes 30.75=4\tfrac{3}{0.75} = 4 full cycles, going between 1313 cm and 4747 cm.

9. (Challenge) Explain why the amplitude is half of (maximum − minimum), using the Ferris wheel as an example.

Solution

The axis is halfway between the maximum and minimum, so the distance from maximum to minimum is made of two equal parts: axis to maximum, and axis to minimum. The amplitude is one of those parts, so it’s half the total.

On a Ferris wheel, the maximum and minimum are a diameter apart, and the amplitude is the radius, half the diameter.